y(t) = 1 2 ay ⋅t2 (1) Electron entering a parallel-plate capacitor? | Yahoo Answers. The distance between the plates is 16.8 cm, and the voltage difference is 130 kV. How many newtons of force push on your head at sea level? The electron lands 4.0 cm away. Determine the final velocity β of the electron using classical mechanics. Determine the final velocity β of the electron using classical mechanics. At the moment t = 0, an electron leaves one plate of a parallel-plate condenser with a negligible velocity. if E = − 1 0 2. ( 9m2eal. Join Yahoo Answers and get 100 points today. An electron is accelerated inside a parallel plate capacitor. … An electron is accelerated inside a parallel plate capacitor. The distance between the plates is 16.8 cm, and the voltage difference is 130 kV. Still have questions? Information about your device and internet connection, including your IP address, Browsing and search activity while using Verizon Media websites and apps. • 6 × 1 0 − 1 9 C travelling with a velocity 1. The electron leaves the negative plate with a negligible initial velocity and then after the acceleration it hits the positive plate with a final velocity β. The figure shows an electron entering a parallel-plate capacitor with a speed of 5.45×106m/s . Completing the CAPTCHA proves you are a human and gives you temporary access to the web property. We and our partners will store and/or access information on your device through the use of cookies and similar technologies, to display personalised ads and content, for ad and content measurement, audience insights and product development. angle and a speed of 5.0×106m/s from the positive plate of the parallel-plate capacitor shown in the figure (Figure 1) . What is the final velocity β of the electron if you use relativistic mechanics? equation of motion in y-direction. • (The rest mass of the electron is 9.11×10-31 kg, the rest energy of the electron is 511 keV.). There are two parallel plates acting as a capacitor, arranged in the y-z plane, one at 0 volts and one at +V volts. This gives K f = 1/2 mv 2 = q ΔV so: v = [ 2qΔV /m ] 1/2. An accelerating voltage varying as V = at, where a is a constant is applied between the plates. You can change your choices at any time by visiting Your Privacy Controls. U i + K i + W nc = U f + K f. There are no non-conservative forces acting, the initial kinetic energy is zero, and we can define the plate where the charge exits the capacitor as the zero of potential energy (i.e., U f = 0). An electron is emitted from the surface of the 0 volt plate, with negligible velocity. Get your answers by asking now. Convert eV to Joules using the fact that 1 ev = 1x10^-19 J, Y = [(130000ev)(1.60x10^-19 J/ev)]/[(9.11x10^-19)(3x10^8)^2] + 1 = 1.254, v = sqrt{1-[1/(1.254)]}c = 1.81x10^8 m/s = .603c = β. To enable Verizon Media and our partners to process your personal data select 'I agree', or select 'Manage settings' for more information and to manage your choices. You may need to download version 2.0 now from the Chrome Web Store. 10 -31 kg. v= velocity = β, V=voltage diff, KE = kinetic energy, Y = gamma, m = mass, and q = charge, v = sqrt(-2qV/m) use this equation and solve for v. It is derived from the fact that KE = Vq, so, v = sqrt[-2(-1.6x10^-19)(130000)/ (9.11x10^-31 )] = 2.14x10^8 m/s = .712c = β. Yahoo is part of Verizon Media. See the answer. Find out more about how we use your information in our Privacy Policy and Cookie Policy. If you are at an office or shared network, you can ask the network administrator to run a scan across the network looking for misconfigured or infected devices. An electron is launched at a 45? physics. Cloudflare Ray ID: 5f88ba92bd34d6f1 The separation between the plates is l. The velocity of the electron at the moment it reaches the opposite plate will be : A . A uniform magnetic field of flux density B field acts parallel to these plates in the z direction. If you are on a personal connection, like at home, you can run an anti-virus scan on your device to make sure it is not infected with malware. KE = (Y-1)mc^2 use this eqn to find gamma (Y) and use v = sqrt[1-(1/Y^2)]c to find the velocity. Your IP: 37.187.171.105 . 4 × 1 0 3 k ^ N C − 1 and B = 8 × 1 0 − 2 j ^ W b m − 2, the direction of motion of the particles is Another way to prevent getting this page in the future is to use Privacy Pass. 2 8 × 1 0 6 m / s along the positive X-axis enters a region in which a uniform electric field E and a uniform magnetic field of induction B are present. The electron leaves the negative plate with a negligible initial velocity and then after the acceleration it hits the positive plate with a final velocity β.

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